GATE BT 2026 • Q64 NAT • 2 Marks

Section 2: General Biotechnology

Biomolecules, enzyme kinetics

Subtopic: Fundamentals of Biomolecules, enzyme kinetics

Question Statement:

A disease-associated allele shows X-linked recessive inheritance. If the mother is a carrier of the disease, the father is genetically normal and the child born is a son, then the probability that he is born with the disease is _______. (rounded off to one decimal place)

Official Answer Key:

0.5 to 0.5

Step-by-Step Solution & Explanation

### **Step-by-Step Solution & Mathematical Derivation (GATE BT 2026 Q.64)** **1. Governing Concept & Definition**: - **Topic**: Human Genetics & X-Linked Recessive Inheritance - Let $X^A$ denote the normal allele and $X^a$ denote the disease-associated recessive allele. - Carrier mother: $X^A X^a$ - Unaffected father: $X^A Y$ **2. Detailed Step-by-Step Calculation**: - **Mating**: $X^A X^a \times X^A Y$ - **Offspring Genotypes**: - Daughters: - $X^A X^A$ (Normal female) - $X^A X^a$ (Carrier female) - Sons: - $X^A Y$ (Normal male) - $X^a Y$ (Affected male) - **Question Condition**: Probability that a son born to this couple is affected: $\text{Among sons: } P(X^a Y) = \frac{1}{2} = 0.5$ **3. Final Answer**: - **Calculated Value**: **0.5** - **Official GATE Accepted Range**: **0.5 to 0.5**

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