GATE BT 2026 • Q23 MCQ • 1 Mark

Section 3: Genetics, Cellular and Molecular Biology

Classical Genetics and Epistasis

Subtopic: Mendelian Genetics & Gene Interactions

Question Statement:

Match the carbohydrates in Column I with the correct glycosidic linkages involved in Column II. Column I Column II P. Amylose 1. β (1 4) Q. Sucrose 2. α (1 4) R. Amylopectin 3. α1 β2 S. Cellulose 4. α (1 4), α (1 6)

Options:

  • (A) P-4; Q-3; R-2; S-1
  • (B) P-2; Q-1; R-4; S-3
  • (C) P-2; Q-3; R-4; S-1
  • (D) P-1; Q-3; R-4; S-2

Official Answer Key:

C

Step-by-Step Solution & Explanation

### **Official Solution & Concept Analysis (GATE BT 2026 Q.23)** **1. Governing Concept**: - **Topic**: Biochemistry & Glycosidic Linkages in Disaccharides - Standard disaccharide glycosidic bond architectures: 1. **Maltose**: Two $\alpha$-$D$-glucopyranose units linked by an **$\alpha(1 \to 4)$** glycosidic bond. 2. **Lactose**: $\beta$-$D$-galactopyranose linked to $\beta$-$D$-glucopyranose via a **$\beta(1 \to 4)$** glycosidic bond. 3. **Sucrose**: $\alpha$-$D$-glucopyranose linked to $\beta$-$D$-fructofuranose via an **$\alpha(1 \leftrightarrow 2)\beta$** non-reducing head-to-head glycosidic linkage. 4. **Trehalose**: Two $\alpha$-$D$-glucose units linked via an **$\alpha(1 \leftrightarrow 1)\alpha$** non-reducing bond. **2. Option Analysis**: - Matching Column I carbohydrates with Column II glycosidic bonds: - Maltose $\rightarrow \alpha(1 \to 4)$ - Lactose $\rightarrow \beta(1 \to 4)$ - Sucrose $\rightarrow \alpha(1 \leftrightarrow 2)\beta$ - **Option (C) is CORRECT**: Perfectly aligns every sugar with its canonical linkage. - **Options (A), (B), and (D) are INCORRECT**: Misassign anomeric configurations ($\alpha$ vs $\beta$) or carbon numbers. **3. Final Answer**: - **Correct Choice**: **C**

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