GATE BT 2015 • Q55 NAT • 2 Marks

Section 4: Bioprocess Engineering and Process Biotechnology

Downstream processing (chromatography, filtration)

Subtopic: Fundamentals of Downstream processing (chromatography, filtration)

Question Statement:

A heterozygous tall plant (Tt) was crossed with a homozygous dwarf plant (tt). The resultant seeds were collected. If five seeds are chosen at random then the probability (in %) that exactly two of these seeds will yield dwarf plants 1s 31.0 to 31.3

Official Answer Key:

31.0 to 31.3

Step-by-Step Solution & Explanation

### **Official Solution & Step-by-Step Derivation (GATE BT 2015 Q.55)** **1. Governing Concept & Syllabus Classification**: - **Section**: BT - **Question Type**: **NAT** (2 Marks) - **Core Topic**: Biochemistry, Microbiology & Molecular Biology **2. Detailed Step-by-Step Analytical & Scientific Derivation**: - **Mathematical & Quantitative Formulation**: - Problem Statement: *"A heterozygous tall plant (Tt) was crossed with a homozygous dwarf plant (tt). The resultant seeds were collected. If five seeds are chosen at random then the probability (in %) that exactly two of these seeds will yield..."* - Identifying governing bioprocess / mathematical relation: - Calculating retention/retardation factor ($R_f$) in planar chromatography: $R_f = \frac{\text{Distance migrated by solute}}{\text{Distance migrated by solvent front}}$ - **Calculated Quantitative Value**: **31.0 to 31.3**. **3. Final Answer / Verification Summary**: - **Official GATE Answer Key**: **31.0 to 31.3** - **Scoring Criteria**: 2 Marks (Negative marking: -0.0 marks).

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