GATE BT 2015 • Q48 NAT • 2 Marks

Section 2: General Biotechnology

Biomolecules, enzyme kinetics

Subtopic: Fundamentals of Biomolecules, enzyme kinetics

Question Statement:

Saccharomyces cerevisiae produces ethanol by fermentation The theoretical yield of ethanol from 2.5 g of glucose is - 8- 1.20 to 1.30l

Official Answer Key:

1.20 to 1.30

Step-by-Step Solution & Explanation

### **Step-by-Step Solution & Mathematical Derivation (GATE BT 2015 Q.48)** **1. Governing Concept & Definition**: - **Topic**: Bioprocess Stoichiometry & Ethanol Fermentation Theoretical Yield - Glycolytic conversion of glucose to ethanol: $\text{C}_6\text{H}_{12}\text{O}_6 \rightarrow 2\text{C}_2\text{H}_5\text{OH} + 2\text{CO}_2$ Theoretical yield $Y_{P/S} = \frac{2 \times 46}{180} = \frac{92}{180} \approx 0.511\text{ g ethanol / g glucose}$. **2. Detailed Step-by-Step Calculation**: - **Given Glucose Consumed**: $2.5\text{ g}$ (or specified scale): $\text{Ethanol Yield} = 2.5 \times 0.511 \approx 1.28\text{ g}$ **3. Final Answer**: - **Calculated Value**: **1.28 g** - **Official GATE Accepted Range**: **1.20 to 1.30**

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