GATE BT 2015 • Q48
NAT • 2 Marks
Section 2: General Biotechnology
Biomolecules, enzyme kinetics
Subtopic: Fundamentals of Biomolecules, enzyme kinetics
Question Statement:
Saccharomyces cerevisiae produces ethanol by fermentation The theoretical yield of ethanol from
2.5 g of glucose is
- 8-
1.20 to 1.30l
Official Answer Key:
1.20 to 1.30
Step-by-Step Solution & Explanation
### **Step-by-Step Solution & Mathematical Derivation (GATE BT 2015 Q.48)**
**1. Governing Concept & Definition**:
- **Topic**: Bioprocess Stoichiometry & Ethanol Fermentation Theoretical Yield
- Glycolytic conversion of glucose to ethanol:
$\text{C}_6\text{H}_{12}\text{O}_6 \rightarrow 2\text{C}_2\text{H}_5\text{OH} + 2\text{CO}_2$
Theoretical yield $Y_{P/S} = \frac{2 \times 46}{180} = \frac{92}{180} \approx 0.511\text{ g ethanol / g glucose}$.
**2. Detailed Step-by-Step Calculation**:
- **Given Glucose Consumed**: $2.5\text{ g}$ (or specified scale):
$\text{Ethanol Yield} = 2.5 \times 0.511 \approx 1.28\text{ g}$
**3. Final Answer**:
- **Calculated Value**: **1.28 g**
- **Official GATE Accepted Range**: **1.20 to 1.30**
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