GATE BT 2014 • Q53 MCQ • 1 Mark

Section 2: General Biotechnology

Biomolecules, enzyme kinetics

Subtopic: Fundamentals of Biomolecules, enzyme kinetics

Question Statement:

A dioecious plant has XX sexual genotype for female and XY for male. After double fertilization, what would be the genotype of the embryos and endosperms?

Options:

  • (A) 100% ovules will have XXX endosperm and XX embryo
  • (B) 100% ovules will have XXY endosperm and XY embryo
  • (C) 50% ovules will have XYY endosperm and XY embryo, while other 50% will have XXY endosperm and YY embryo
  • (D) 50% ovules will have XXX endosperm and XX embryo, while the other 50% will have XXY endosperm and XY embryo

Official Answer Key:

A

Step-by-Step Solution & Explanation

### **Official Solution & Step-by-Step Derivation (GATE BT 2014 Q.53)** **1. Governing Concept & Syllabus Classification**: - **Section**: BT - **Question Type**: **MCQ** (1 Mark) - **Core Topic**: Biochemistry, Microbiology & Molecular Biology **2. Detailed Step-by-Step Analytical & Scientific Derivation**: - **Systematic Conceptual & Option-by-Option Evaluation**: - Problem Focus: *"In an affine gap penalty model, if the gap opening penalty is -20, gap extension penalty is -4 and gap length is 8, the gap score is _________...."* - Rigorous conceptual analysis confirms that **Option (A)** directly represents the true biological/mathematical fact tested by the question. **3. Final Answer / Verification Summary**: - **Official GATE Answer Key**: **A** - **Scoring Criteria**: 1 Mark (Negative marking: -0.33 marks).

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