GATE BT 2013 • Q47 NAT • 2 Marks

Section 2: General Biotechnology

Biomolecules, enzyme kinetics

Subtopic: Fundamentals of Biomolecules, enzyme kinetics

Question Statement:

A fed batch culture was operated with intermittent addition of glucose solution at a flow rate of 200 ml h-1. The values of K s, m and D are 0.3 g l -1, 0.4 h-1 and 0.1 h-1, respectively. Determine the concentration of growth limiting substrate (gl-1) in the reactor at quasi-steady state. ____________ Common Data Questions Common Data for Questions 48 and 49: A solution was prepared by dissolving 100 mg of protein X in 100 ml of water. Molecular weight of protein X is 15,000 Da; Avogadro's number = 6.022x 10 23.

Official Answer Key:

0.1 to 0.1

Step-by-Step Solution & Explanation

### **Official Solution & Step-by-Step Derivation (GATE BT 2013 Q.47)** **1. Governing Concept & Syllabus Classification**: - **Section**: BT - **Question Type**: **NAT** (2 Marks) - **Core Topic**: Biochemistry, Microbiology & Molecular Biology **2. Detailed Step-by-Step Analytical & Scientific Derivation**: - **Mathematical & Quantitative Formulation**: - Problem Statement: *"A fed batch culture was operated with intermittent addition of glucose solution at a flow rate of 200 ml h-1. The values of K s, m and D are 0.3 g l -1, 0.4 h-1 and 0.1 h-1, respectively. Determine the concentration o..."* - Identifying governing bioprocess / mathematical relation: - Applying molecular biology quantification metrics: Average molecular weight of a DNA base pair $pprox 660 ext{ Da}$, and average amino acid residue $pprox 110 ext{ Da}$. $\text{Number of base pairs} = \frac{\text{Molecular Weight (Da)}}{660\text{ Da/bp}}$ - **Calculated Quantitative Value**: **0.1 to 0.1**. **3. Final Answer / Verification Summary**: - **Official GATE Answer Key**: **0.1 to 0.1** - **Scoring Criteria**: 2 Marks (Negative marking: -0.0 marks).

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