Subtopic: Discrete & Continuous Probability Distributions
Question Statement:
What will be the probability of having the colour-blind daughter to a phenotypically
man?
normal woman, who already had one colour-blind son, and is married to a colour-blind
Options:
(A) 75 %
(B) 50 %
(C) 25 %
(D) 15%
Common Data for Questions 50 and 51:
A microorganism grows in a continuous 'chemostat' culture of 60 m' working volume with
sucrose as the growth limiting nutrient at dilution rate, D = 0.55 h''. The steady state biomass
concentration is 4.5 Kg dry biomass m'3
and the residual sucrose concentration is 2.0 Kg m°'. The
sucrose concentration in the incoming feed medium is 10.0 Kg m-3
Official Answer Key:
C
Step-by-Step Solution & Explanation
### **Official Solution & Step-by-Step Derivation (GATE BT 2011 Q.49)**
**1. Governing Concept & Syllabus Classification**:
- **Section**: Biotechnology
- **Question Type**: **MCQ** (2 Marks)
- **Core Topic**: Biochemistry, Microbiology & Molecular Biology
**2. Detailed Step-by-Step Analytical & Scientific Derivation**:
- **Systematic Conceptual & Option-by-Option Evaluation**:
- Problem Focus: *"What will be the probability of having the colour-blind daughter to a phenotypically
man?
normal woman, who already had one colour-blind son, and is married to a colour-blind..."*
- **Option (C) [CORRECT]**: *"25 %"*
- Validated by canonical biochemistry/biotechnology literature. Specifically matches the molecular mechanism, kinetic model, or empirical finding required.
- **Option (A) [INCORRECT]**: *"75 %"* does not satisfy the precise boundary conditions or molecular specificity.
- **Option (B) [INCORRECT]**: *"50 %"* does not satisfy the precise boundary conditions or molecular specificity.
- **Option (D) [INCORRECT]**: *"15%
Common Data for Questions 50 and 51:
A microorganism grows in a continu"* does not satisfy the precise boundary conditions or molecular specificity.
**3. Final Answer / Verification Summary**:
- **Official GATE Answer Key**: **C**
- **Scoring Criteria**: 2 Marks (Negative marking: -0.66 marks).
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