GATE BT 2023 • Q59
NAT • 2 Marks
Section 1: Engineering Mathematics
Calculus
Subtopic: Fundamentals of Calculus
Question Statement:
If
sin cos() sin cos
xxfx xx
+= - , the value of
()fx at
0x= is ___________.
Official Answer Key:
-2 to -2
Step-by-Step Solution & Explanation
### **Step-by-Step Solution & Mathematical Derivation (GATE BT 2023 Q.59)**
**1. Governing Concept & Definition**:
- **Topic**: Engineering Mathematics & Quotient Rule of Differentiation
- For a rational function $f(x) = \frac{u(x)}{v(x)}$, the derivative is:
$f'(x) = \frac{u'(x)v(x) - u(x)v'(x)}{[v(x)]^2}$
**2. Detailed Step-by-Step Calculation**:
- **Given Function**:
$f(x) = \frac{\sin x + \cos x}{\sin x - \cos x}$
- $u(x) = \sin x + \cos x \implies u'(x) = \cos x - \sin x$
- $v(x) = \sin x - \cos x \implies v'(x) = \cos x + \sin x$
- **Evaluate components at $x = 0$**:
- $\sin 0 = 0$, $\cos 0 = 1$
- $u(0) = 0 + 1 = 1$
- $u'(0) = 1 - 0 = 1$
- $v(0) = 0 - 1 = -1$
- $v'(0) = 1 + 0 = 1$
- **Substitution into Quotient Rule**:
$f'(0) = \frac{(1)(-1) - (1)(1)}{(-1)^2} = \frac{-1 - 1}{1} = -2$
**3. Final Answer**:
- **Calculated Value**: **-2**
- **Official GATE Accepted Range**: **-2 to -2**
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