GATE BT 2023 • Q48 NAT • 2 Marks

Section 4: Bioprocess Engineering and Process Biotechnology

Bioreactor types, scale-up

Subtopic: Fundamentals of Bioreactor types, scale-up

Question Statement:

E. coli is cultivated in a chemostat operated at a dilution rate of 10.2 h- . The values of biomass yield due to oxygen consumption and the steady state biomass concentration are 10.2 .gg - and 110 .gL - , respectively. The oxygen transfer rate (in 11..g L h-- ) is ___________.

Official Answer Key:

10 to 10

Step-by-Step Solution & Explanation

### **Official Solution & Step-by-Step Derivation (GATE BT 2023 Q.48)** **1. Governing Concept & Syllabus Classification**: - **Section**: BT - **Question Type**: **NAT** (2 Marks) - **Core Topic**: Bioprocess Engineering **2. Detailed Step-by-Step Analytical & Scientific Derivation**: - **Mathematical & Quantitative Formulation**: - Problem Statement: *"E. coli is cultivated in a chemostat operated at a dilution rate of 10.2 h- . The values of biomass yield due to oxygen consumption and the steady state biomass concentration are 10.2 .gg - and 110 .gL - , respectiv..."* - Identifying governing bioprocess / mathematical relation: - In a continuous stirred tank bioreactor (chemostat) at steady state: $\mu = D = \frac{F}{V}$ where $\mu$ is the specific growth rate ($ ext{h}^{-1}$), $D$ is the dilution rate, $F$ is volumetric feed flow rate, and $V$ is working volume. $S = \frac{K_s D}{\mu_{max} - D}, \quad X = Y_{X/S}(S_0 - S)$ - **Calculated Quantitative Value**: **10 to 10**. **3. Final Answer / Verification Summary**: - **Official GATE Answer Key**: **10 to 10** - **Scoring Criteria**: 2 Marks (Negative marking: -0.0 marks).

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