GATE BT 2023 • Q30 NAT • 1 Mark

Section 1: Engineering Mathematics

Probability and Statistics

Subtopic: Discrete & Continuous Probability Distributions

Question Statement:

A double reciprocal Lineweaver-Burk plot of an uninhibited enzyme catalyzed reaction has a y-intercept of 0.2 (µmol/min)^-1 and an x-intercept of -0.5 mM^-1. The value of Vmax in µmol/min is ________.

Official Answer Key:

25 to 25

Step-by-Step Solution & Explanation

### **Step-by-Step Solution & Mathematical Derivation (GATE BT 2023 Q.30)** **1. Governing Concept & Definition**: - **Topic**: Human Genetics & X-Linked Recessive Inheritance - Let $X^D$ denote the normal allele and $X^d$ denote the recessive allele causing Fabry disease. - Phenotypically normal father: Genotype $X^D Y$ - Carrier mother: Genotype $X^D X^d$ **2. Detailed Step-by-Step Calculation**: - **Parental Cross**: $X^D Y \times X^D X^d$ - **Possible Offspring Genotypes & Probabilities**: - $X^D X^D$ (Normal female): $25\%$ ($1/4$) - $X^D X^d$ (Carrier female): $25\%$ ($1/4$) - $X^D Y$ (Normal male): $25\%$ ($1/4$) - $X^d Y$ (Affected male with Fabry disease): $25\%$ ($1/4$) - **Probability of having a son with Fabry disease**: - Across all children born to this couple, the probability that a child is both a son and affected ($X^d Y$) is: $P(\text{affected son}) = \frac{1}{4} = 0.25 = 25\%$ **3. Final Answer**: - **Calculated Value**: **25%** - **Official GATE Accepted Range**: **25 to 25**

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