GATE BT 2021 • Q48 MSQ • 2 Marks

Section 2: General Biotechnology

Biomolecules, enzyme kinetics

Subtopic: Fundamentals of Biomolecules, enzyme kinetics

Question Statement:

Which of the following nucleus/nuclei is/are NMR active?

Options:

  • (A) 'H
  • (B) 13C
  • (C) 160
  • (D) 325

Official Answer Key:

A,B

Step-by-Step Solution & Explanation

### **Official Solution & Concept Analysis (GATE BT 2021 Q.48)** **1. Governing Concept**: - **Topic**: Biophysical Techniques & NMR-Active Nuclei Selection Rules - An atomic nucleus is **NMR-active** (possesses a non-zero nuclear spin quantum number $I \neq 0$) if and only if it has an odd number of protons, an odd number of neutrons, or both: - If **both atomic number $Z$ and mass number $A$ are even**, the nuclear spin $I = 0$ (NMR-inactive). - Evaluating isotopes: 1. **$^1\text{H}$**: $Z=1, A=1$ (odd $A$) $\implies I = 1/2$ (**NMR-active**). 2. **$^{13}\text{C}$**: $Z=6, A=13$ (odd $A$) $\implies I = 1/2$ (**NMR-active**). 3. **$^{15}\text{N}$**: $Z=7, A=15$ (odd $A$) $\implies I = 1/2$ (**NMR-active**). 4. **$^{31}\text{P}$**: $Z=15, A=31$ (odd $A$) $\implies I = 1/2$ (**NMR-active**). 5. **$^{12}\text{C}$**: $Z=6, A=12$ (even $Z$, even $A$) $\implies I = 0$ (**NMR-inactive**). 6. **$^{16}\text{O}$**: $Z=8, A=16$ (even $Z$, even $A$) $\implies I = 0$ (**NMR-inactive**). **2. Option Analysis**: - **Option (A) [1H] is CORRECT**: Spin $I = 1/2$, the most common nucleus used in biological NMR. - **Option (B) [13C] is CORRECT**: Spin $I = 1/2$, widely used in carbon heteronuclear NMR. - **Option (C) [12C] is INCORRECT**: Spin $I = 0$ (even-even nucleus), completely NMR-silent. - **Option (D) [16O] is INCORRECT**: Spin $I = 0$ (even-even nucleus), completely NMR-silent. **3. Final Answer**: - **Correct Options**: **A, B**

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