GATE BT 2019 • Q57 NAT • 2 Marks

General Aptitude

Quantitative Aptitude

Subtopic: Data Interpretation

Question Statement:

In pea plants, purple color of flowers is determined by the dominant allele while white color is determined by the recessive allele. A genetic cross between two purple flower- bearing plants results in an offspring with white flowers. The probability that the third offspring from these parents will have purple flowers is (rounded off to 2 decimal

Official Answer Key:

0.75 to 0.75

Step-by-Step Solution & Explanation

### **Step-by-Step Solution & Mathematical Derivation (GATE BT 2019 Q.57)** **1. Governing Concept & Definition**: - **Topic**: Classical Mendelian Genetics & Monohybrid Cross - Let $P$ be the dominant allele for purple flowers and $p$ be the recessive allele for white flowers. - Heterozygous plant genotype: $Pp$ - Cross: $Pp \times Pp$. **2. Detailed Step-by-Step Calculation**: - **Genotypic Ratio**: $1\text{ }PP : 2\text{ }Pp : 1\text{ }pp$ - **Phenotypes**: - Purple flower phenotype ($PP$ and $Pp$): $\frac{1}{4} + \frac{2}{4} = \frac{3}{4} = 0.75$ - White flower phenotype ($pp$): $\frac{1}{4} = 0.25$ - The probability that a random progeny plant has purple flowers is $0.75$. **3. Final Answer**: - **Calculated Value**: **0.75** - **Official GATE Accepted Range**: **0.75 to 0.75**

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