GATE BT 2018 • Q7 MCQ • 2 Marks

General Aptitude

Quantitative Aptitude

Subtopic: Data Interpretation

Question Statement:

A set of 4 parallel lines intersect with another set of 5 parallel lines. How many parallelograms are formed? (A) 20 (B) 48 (C) 60 (D) 72

Options:

  • (A) 20
  • (B) 48
  • (C) 60
  • (D) 72

Official Answer Key:

C

Step-by-Step Solution & Explanation

### **Official Solution & Step-by-Step Derivation (GATE BT 2018 Q.07)** **1. Governing Concept & Question Classification**: - **Section**: General Aptitude (GA) - **Question Type**: **MCQ** (2 Marks) - **Topic**: Combinatorics (Forming Parallelograms from Intersecting Parallel Lines) **2. Detailed Step-by-Step Derivation**: - A parallelogram is formed by choosing two lines from one set of parallel lines and two lines from an intersecting set of parallel lines. - Number of lines in the first parallel set = $m = 4$. - Number of ways to choose 2 lines from the first set: $inom{4}{2} = rac{4 imes 3}{2 imes 1} = 6$ - Number of lines in the second parallel set = $n = 5$. - Number of ways to choose 2 lines from the second set: $inom{5}{2} = rac{5 imes 4}{2 imes 1} = 10$ - By the fundamental principle of counting, total number of distinct parallelograms formed: $N = inom{4}{2} imes inom{5}{2} = 6 imes 10 = 60$ - **Option-by-Option Evaluation**: - **Option (A) [INCORRECT]**: 20 equals $4 imes 5$, which is the number of intersection points, not parallelograms. - **Option (B) [INCORRECT]**: 48 is an incorrect combinatorial product. - **Option (C) [CORRECT]**: 60 is the exact number of parallelograms formed ($inom{4}{2} imes inom{5}{2} = 60$). - **Option (D) [INCORRECT]**: 72 is an erroneous combinatorial estimate. **3. Final Answer / Verification Summary**: - **Official GATE Answer Key**: **C** - **Scoring Criteria**: +2.0 Marks (Negative marking: -0.67 marks).

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