GATE BT 2018 • Q58 NAT • 2 Marks

General Aptitude

Quantitative Aptitude

Subtopic: Data Interpretation

Question Statement:

Mammalian cells in active growth phase were seeded at a density of 1105 cells/ml. After 72 hours, 1106 cells/ml were obtained. The population doubling time of the cells in hours is (up to two decimal places) _________

Official Answer Key:

21.00 to 22.00

Step-by-Step Solution & Explanation

### **Step-by-Step Solution & Mathematical Derivation (GATE BT 2018 Q.58)** **1. Governing Concept & Definition**: - **Topic**: Animal Cell Culture & Population Doubling Time - Cell proliferation follows: $N(t) = N_0 \cdot 2^{t / t_d} \implies t_d = \frac{t \ln 2}{\ln(N(t)/N_0)}$ **2. Detailed Step-by-Step Calculation**: - **Given**: - Seeding density $N_0 = 1 \times 10^5\text{ cells/mL}$ - Final density $N(72) = 1 \times 10^6\text{ cells/mL}$ (10-fold increase) - Time elapsed $t = 72\text{ hours}$ - **Doubling Time**: $t_d = \frac{72 \times \ln 2}{\ln(10)} = \frac{72 \times 0.69315}{2.302585} = \frac{49.907}{2.302585} \approx 21.67\text{ hours}$ **3. Final Answer**: - **Calculated Value**: **21.7 hours** - **Official GATE Accepted Range**: **21.00 to 22.00**

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