GATE BT 2018 β’ Q51
NAT β’ 2 Marks
Section 1: Engineering Mathematics
Calculus
Subtopic: Fundamentals of Calculus
Question Statement:
Calculate the following integral (up to two decimal places)
β«(π₯+ 3)(π₯+ 1)ππ₯=
1
0
_________
Official Answer Key:
5.30Β toΒ 5.34
Step-by-Step Solution & Explanation
### **Step-by-Step Solution & Mathematical Derivation (GATE BT 2018 Q.51)**
**1. Governing Concept & Definition**:
- **Topic**: Engineering Mathematics & Definite Integrals
- Evaluating the polynomial integral:
$\int_0^1 (x + 3)(x + 1)\,dx$
**2. Detailed Step-by-Step Calculation**:
- **Expand the integrand**:
$(x + 3)(x + 1) = x^2 + 4x + 3$
- **Integrate term by term**:
$\int_0^1 (x^2 + 4x + 3)\,dx = \left[ \frac{x^3}{3} + 2x^2 + 3x \right]_0^1$
- **Evaluate at limits**:
$\left( \frac{1^3}{3} + 2(1)^2 + 3(1) \right) - 0 = \frac{1}{3} + 2 + 3 = \frac{1}{3} + 5 = \frac{16}{3} \approx 5.333 \approx 5.33$
**3. Final Answer**:
- **Calculated Value**: **5.33**
- **Official GATE Accepted Range**: **5.30 to 5.34**
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