GATE BT 2017 • Q21 MCQ • 1 Mark

Section 2: General Biotechnology

Biomolecules, enzyme kinetics

Subtopic: Fundamentals of Biomolecules, enzyme kinetics

Question Statement:

An enzymatic reaction exhibits Michaelis-Menten kinetics. For this reaction, on doubling the concentration of enzyme while maintaining [S] >> [Eo].

Options:

  • (A) both Km and Vmax will remain the same.
  • (B) Km will remain the same but max will increase.
  • (C) Km will increase but max will remain the same.
  • (D) both Km and max will increase.

Official Answer Key:

B

Step-by-Step Solution & Explanation

### **Official Solution & Step-by-Step Derivation (GATE BT 2017 Q.21)** **1. Governing Concept & Question Classification**: - **Section**: BT - **Question Type**: **MCQ** (1 Mark) - **Topic**: Biochemistry / Enzyme Kinetics (Michaelis-Menten Parameters: $K_m$ and $V_{\max}$) **2. Detailed Step-by-Step Derivation**: - In Michaelis-Menten enzyme kinetics: $v = \frac{V_{\max}[S]}{K_m + [S]}$ - The maximum velocity is directly proportional to the total active enzyme concentration $[E_0]$: $V_{\max} = k_{\text{cat}} [E_0]$ where $k_{\text{cat}}$ is the turnover number (a constant intrinsic to the enzyme). - If the concentration of enzyme is doubled ($[E_0]' = 2[E_0]$): $V_{\max}' = k_{\text{cat}} [E_0]' = 2 k_{\text{cat}} [E_0] = 2 V_{\max}$ Therefore, $V_{\max}$ doubles (increases). - The Michaelis constant, $K_m = \frac{k_{-1} + k_{\text{cat}}}{k_1}$, represents the substrate concentration at which $v = V_{\max}/2$. - $K_m$ is an **intrinsic characteristic constant** of the enzyme-substrate pair reflecting the affinity under defined temperature, pH, and ionic strength, and is **completely independent of total enzyme concentration $[E_0]$**. - Thus, doubling the enzyme concentration causes **$K_m$ to remain the same while $V_{\max}$ increases**. - **Option-by-Option Evaluation**: - **Option (A) [INCORRECT]**: $V_{\max}$ is directly proportional to $[E_0]$ and therefore cannot remain the same when $[E_0]$ doubles. - **Option (B) [CORRECT]**: $K_m$ is an intrinsic kinetic constant and remains unchanged, whereas $V_{\max}$ doubles with doubled $[E_0]$. - **Option (C) [INCORRECT]**: $K_m$ does not depend on enzyme concentration. - **Option (D) [INCORRECT]**: $K_m$ does not increase with enzyme concentration. **3. Final Answer / Verification Summary**: - **Official GATE Answer Key**: **B** - **Scoring Criteria**: +1.0 Mark (Negative marking: -0.33 marks).

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